# Line slope calculator 5x+2y=26

**Straight line given by points A[2; 8] and B[4; 3]**

## Calculation:

**Slope-intercept form of line:**y = -2.5x+13

**Canonical form of the line equation:**5x+2y-26 = 0

**Parametric form of the line equation:**

x = 2t+2

y = -5t+8 ; t ∈ R

**Slope:**m = -2.5

**Slope angle of line: φ =**-68°11'55″ = -1.1903 rad

**X intercept:**x

_{0}= 5.2

**Y intercept:**y

_{0}= q = 13

**Distance line from the origin:**d

_{0}= 4.8281

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(2; -5)

**Normal vector: n =**(5; 2)

**Midpoint of the segment AB: M =**[3; 5.5]

**Perpendicular Bisector equation:**2x-5y+21.5 = 0

**Vector OA = (2; 8) ; |OA| = 8.2462**

**Vector OB = (4; 3) ; |OB| = 5**

**Scalar product OA .OB = 32**

**Angle ∠ AOB = 39°5'38″ = 0.6823 rad**